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Correct-F/Maths obj
1BADBCABADD
11DCBBBCBBDB
21CCADAAADDB
31ADDDBCADDA
(9b) n+1(n-1=
28)
(n+1)(n)(n-1) !
-------------------
(n+1-n+1)!
n+1
------ = 28
2!
n+1= 56
n= 56-1 = 55
(2)
2^(2x + 2) + 3(2^x) - 1 = 0
2^2x X 2^2 + 3(2^x) - 1 = 0
(2^x)^2 + 3(2^x) - 1 = 0
Let 2^x = y
Y^2 X 4 + 3y - 1 = 0
4y^2 + 3y - 1 = 0
4y^2 + 4y - y - 1 = 0
4y(y+1) - 1(y+1) = 0
(4y-1)(y+1) = 0
4y - 1 = 0 or y + 1 = 0
4y =1 or y= -1
Y = 1/4 or -1
Recall
2^x = y when y = 1/4
2^x = 1/4
2^x = 2^-2
X = -2
When Y = -1
It has bo solution
:- x = -2
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1.
F(x)=4n+5/2n+1
G(x)=3n+1
a.F°g=4(3n+1)+5/2(3x+1)+1
=12x+9/6x+3
=1(4x+3)/1(2x+1)
=4x+3/2x+1
b.
If f°g=h(x)=y
Y=4x+3/2x+1
(2x+1)y=4x+3
2xy+y=4n+3
2xy-4x=3-y
X=3-y/2y-4
X=3-y/2(y-2)
Inverse of f°g=h^-1(x)=3-x/2(x-2).
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(3)
4x-5/(x-2)^2=A/x-2+B/(x-2)
4x-5/(x-2)^2=A(x(n-2)+B/(n-2)^2
4x-5=a(x-2)+b
4x-5=ax-2a+b
Comparing the coefficient
A=4
-2a+b=-5
-2(4)+b=-5
-8+b=-5
B=-5+8=3
: 4x-5/(x-2)^2=4/x-2+3/(x-2)^2
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WAEC GCE Further Mathematics Expo Answers & Questions 2017 (Complete Further Mathematics OBJ/Theory Runz)
(4)
a=2.5, ar^4=40
Sbase8=a(r^n-1)/r-1
=2.5(2^8-1)/2-1
=2.5(255)/1
=637.5
r^4=40/2.5
r^4=16
r=2
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(6)
P(x) = s/n
P(xny) = 2/5
P(xny) = p(x) x p(y)
2/5 = 3/7 x p(y)
P(y) = 2/5 x 7/3 = 14/15
(A) p(x) = 14/15
(B) p(xuy) = p(x) + p(x)
= 3/7 + 14/15
45 + 98/105 = 143/105
